g(x) = 6x - 1
Maka (f o g)(4/5)?
tolong dibantu
Penyelesaian:
f(g(x))=3(6x-1)³
f(g(x))=3(6x-1)(6x-1)(6x-1)
f(g(x))=3(36x²-12x+1)(6x-1)
f(g(x))=3(216x³-108x²+18x-1)
(f o g)(4/5)=3(216(0,512)-108(0,64)+18(0,8)-1)
(f o g)(4/5)=3(54,872)
(f o g)(4/5)=164,616
[tex] \boxed{ \colorbox{black}{ \sf{ \color{lightgreen}{ answered\:by\:Duone}}}} [/tex]
Penjelasan dengan langkah-langkah:
[tex]f(x) = 3 {x}^{3} [/tex]
[tex]g(x) = 6x - 1[/tex]
[tex] \: [/tex]
• Mencari fog(4/5).
[tex](f \circ g)(\frac{4}{5} ) = f(g( \frac{4}{5} ))[/tex]
[tex] = 3 {x}^{3} [/tex]
[tex] = 3 {(6x - 1)}^{3} [/tex]
[tex] = 3 {(6. \frac{4}{5} - 1)}^{3} [/tex]
[tex] = 3.( \frac{24}{5} - \frac{5}{5} ) {}^{3} [/tex]
[tex] = 3. {( \frac{19}{5} )}^{3} [/tex]
[tex] = 3. \frac{ {19}^{3} }{ {5}^{3} } [/tex]
[tex] = 3. \frac{6.859}{125} [/tex]
[tex] = \frac{20.577}{125} [/tex]
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